2m^2-7m-6=0

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Solution for 2m^2-7m-6=0 equation: 



2m^2-7m-6=0

a = 2; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·2·(-6)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{97}}{2*2}=\frac{7-\sqrt{97}}{4}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{97}}{2*2}=\frac{7+\sqrt{97}}{4}
$

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